a) \(K_2O+H_2O->2KOH\)

b) \(2Fe+3Cl_2->2FeCl_3\)

c) \(2Al\left(OH\right)_3+3H_2SO_4->Al_2\left(SO_4\right)_3+6H_2O\)

d) \(4FeS_2+11O_2->2Fe_2O_3+8SO_2\)

e)\(2Al+6HCl->2AlCl_3+3H_2\)

f) \(2KClO_3->KCl+3O_2\)

g) \(4P+5O_2->2P_2O_5\)

h) \(3Fe+2O_2->Fe_3O_4\)

i) \(2Al+3CuSO_4->Al_2\left(SO_4\right)_3+3Cu\)

j) \(2K+2H_2O->2KOH+H_2\)

`Fe + 2HCl -> FeCl_2 + H_2`

`2Na + 2HCl -> 2NaCl + H_2`

`2Al + 6HCl -> 2AlCl_3 + 3H_2`

`2Al(OH)_3 + 3H_2SO_4 -> Al_2(SO_4)_3 + 6H_2O`

Fe + 2HCl → FeCl₂ + H₂
2Na + 2HCl → 2NaCl + H₂
2Al + 6HCl → 2AlCl₃ + 3H₂
2Al + 3H₂SO₄ → Al₂(SO₄)₃ + 6H₂O

\(Fe+2HCl\rightarrow FeCl_2+H_2\)

\(2Na+2HCl\rightarrow2NaCl+H_2\)

\(2Al+6HCl\rightarrow2AlCl_3+3H_2\)

\(2Al\left(OH\right)_3+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+6H_2O\)

\(1:2n+O_2\rightarrow2nO\)

2: \(2Fe+3Cl_2\rightarrow2FeCl_3\)

3: \(Mg+2HCl\rightarrow MgCl_2+H_2\)

4: \(2Al+6HCl\rightarrow2AlCl_3+3H_2\)

5: \(2Al+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+3H_2\)

1:2n+O2 to→2nO

2: 2Fe+3Cl2 to→2FeCl3

3: Mg+2HCl to→MgCl2+H2

4: 2Al+6HCl →2AlCl3+3H2

5: 2Al+3H2SO4 →Al2(SO4)3+3H2

1) $2n+O_2\to 2nO$

2) $\mathrm{2F}e+\mathrm{3C}{l}_2\to \mathrm{2F}eC{l}_3$

3) $Mg+\mathrm{2H}Cl\to MgC{l}_2+H_2$

4) $\mathrm{2A}l+\mathrm{6H}Cl\to \mathrm{2A}lC{l}_3+{\mathrm{3H}}_2$

5) $\mathrm{2A}l+{\mathrm{3H}}_{2}S{O}_4\to A{l}_2{\left(S{O}_4\right)}_{{}_3}+{\mathrm{3H}}_2$

1. 2Al + 3O₂ \(\rightarrow\) 2AlCl₃

tỉ lệ 2:3:2

2. 2Fe + 3Cl₂ \(\rightarrow\) 2FeCl₃

tỉ lệ 2:3:2

3. 2Na + 2H₂O \(\rightarrow\) 2NaOH + H₂

tỉ lệ 2:2:2

4. Zn + 2HCl \(\rightarrow\) ZnCl₂ + H₂

tỉ lệ 1:2:1:1

5. 2C_xH_y + (2x+y/2)O₂ \(\rightarrow\) 2xCO₂ + yH₂O

tỉ lệ 2:(2x+y/2):2x:y

6.P₂O₅ + 3H₂O \(\rightarrow\) 2H₃PO₄

tỉ lệ 1:3:2

7. Fe₂(SO₄)₃ + 6KOH \(\rightarrow\) 2Fe(OH)₃ + 3K₂SO₄

tỉ lệ 1:6:2:3

8. 2Fe + 3Cl₂ \(\rightarrow\) 2FeCl₃

tỉ lệ 2:3:2

9. 2C_nH_2n-2 + (n-1)O₂ \(\rightarrow\) 2nCO₂ + 2(n-1)H₂O

tỉ lệ 2:(n-1):2n:2(n-1)

10. N₂O₅ + H₂O \(\rightarrow\) 2HNO₃

tỉ lệ 1:1:2

11. FeCl₃ + 3NaOH \(\rightarrow\) Fe(OH)₃ + NaCl

tỉ lệ 1:3:1:1

12. 2Al + 3Cl₂ \(\rightarrow\) 2AlCl₃

tỉ lệ 2:3:2

$\rm k)2KMnO_4 \xrightarrow{t^o} K_2MnO_4 + MnO_2 + O_2 \uparrow$
$\rm l)CH_4 + 2O_2 \xrightarrow{t^o} CO_2 + 2H_2O$
$\rm m)2Al + 3H_2SO_4 \rightarrow Al_2(SO_4)_3 + 3H_2 \uparrow$
$\rm n)Na_2CO_3 + CaCl_2 \rightarrow CaCO_3 \downarrow + 2NaCl$
$\rm o)2Na + 2H_2O \rightarrow 2NaOH + H_2 \uparrow$
$\rm p)CaO + 2HNO_3 \rightarrow Ca(NO_3)_2 + H_2O$
$\rm q)P_2O_5 + 3H_2O \rightarrow 2H_3PO_4$
$\rm r)Zn + 2HCl \rightarrow ZnCl_2 + H_2 \uparrow$
$\rm s)4Al + 3O_2 \xrightarrow{t^o} 2Al_2O_3$
$\rm t)Ba(OH)_2 + 2HCl \rightarrow BaCl_2 + 2H_2O$

a. 4P + 5O₂ \(\underrightarrow{t^o}\) 2P₂O₅

b. 4Al + 3O₂ \(\underrightarrow{t^o}\) 2Al₂O₃

c. Fe + 2HCl \(\rightarrow\) FeCl₂ + H₂\(\uparrow\)

d. H₂ + CuO \(\underrightarrow{t^o}\) Cu + H₂O

e. 3CO + Fe₂O₃ \(\underrightarrow{t^o}\) 2Fe + 3CO₂\(\uparrow\)

f. Cu + 2H₂SO₄ \(\rightarrow\) CuSO₄ + SO₂\(\uparrow\) + 2H₂O

g. Fe + 4HNO₃ \(\rightarrow\) Fe(NO₃)₃ + NO\(\uparrow\) + 2H₂O

h. 2Al + 3H₂SO₄ \(\rightarrow\) Al₂(SO₄)₃ + 3H₂\(\uparrow\)

i. Ca(HCO₃)₂ \(\underrightarrow{t^o}\) CaCO₃ + CO₂\(\uparrow\) + H₂O

à, sorry nha, lo làm cái kia nên quên lun ><

a, b là phản ứng hoá hợp

c, d, h là phản ứng thế

i là phản ứng phân huỷ

a, 4P + 5O₂ ---> 2P₂O₅

b, 4Al + 3O₂ ---> 2Al₂O₃

c, Fe + 2HCl ---> FeCl₂ + H₂

d, H₂ + CuO ---> Cu + H₂O

e, 2CO + Fe₂O₃ ---> 2CO₂ + 2Fe

f, Cu + 2H₂SO₄ ---> CuSO₄ + SO₂ + 2H₂O

g, Fe + 4HNO₃ ---> Fe(NO₃)₃ + NO + 2H₂O

h, 2Al + 3H₂SO₄ --> Al₂(SO₄)₃ + 3H₂

i, Ca(HCO₃)₂ ---> CaCO₃ + CO₂ + H₂O

2Al + 6H₂SO₄ → Al₂(SO₄)₃ + 3SO₂ + 6H₂O

CaCO₃ \(\underrightarrow{to}\) CaO + CO₂

2Al(OH)₃ \(\underrightarrow{to}\) Al₂O₃ + 3H₂O

3Cu + 8HNO₃ → 3Cu(NO₃)₂ + 2NO + 4H₂O

4P + 5O₂ \(\underrightarrow{to}\) 2P₂O₅

2Al(OH)₃ + 3H₂SO₄ → Al₂(SO₄)₃ + 6H₂O

2AlCl₃ + 3Ba(OH)₂ → 3BaCl₂ + 2Al(OH)₃

2Na₃PO₄ + 3CaCl₂ → 6NaCl + Ca₃(PO₄)₂

Bạn viết sai một số công thức, lần sau chú ý hơn nhé!

Cân bằng các phương trình hoa học sau:
$\mathrm{2A}l+\; 6\mathrm{H2}S{O}_4->A{l}_2{\left(S{O}_4\right)}_3+\; 3S{O}_2+\; 6H_{2}O$

$CaC{O}_3->Ca{O}_2+C{O}_2$

$\mathrm{2A}\mathrm{l(}O{\mathrm{H)}}_3->A{l}_2{O}_3+\; 3H_{2}O$

$\mathrm{3C}u+\; 8HN{O}_3->\; 3Cu{\left(N{O}_3\right)}_2+\; 2NO+\; 4H_{2}O$

$\mathrm{4P}+\; 5O_2->\; 2P_2{O}_5$

$\mathrm{2A}\mathrm{l(}O{\mathrm{H)}}_3+\; 3H_{2}S{O}_4->A{l}_2{\left(S{O}_4\right)}_3+\; 6H_{2}O$

$\mathrm{2A}lC{l}_3+\; 3BaO{H}_2->\; 3AlO{H}_3+\; 2BaC{l}_2$

$\mathrm{2N}{a}_{3}P{O}_4+\mathrm{C3}aC{l}_2->\; 6NaCl+C{a}_3{\left(P{O}_4\right)}_2$

1, (1) 4Al+ 3O2--(to)---> 2Al2O3

(2) Al2O3+6HCl---> 2AlCl3+ 3H2O

(3) AlCl3+3NaOH---->Al(OH)3+ 3NaCl

(4) 2Al(OH)3---(t^o)---> Al2O3+ 3H2O

(5)2Al2O3---(t^o+ đpnc)--> 4Al+ 3O2

(6) 2Al+ 3Cl2---> 2AlCl3

2, (1)Fe+ CuSO4-->Cu+ FeSO4

(2) FeSO4+ 2NaOH--> Fe(OH)2+ Na2SO4

(3) Fe(OH)2 +2HCl---> FeCl2+ 2H2O

Bài cuối tự làm nhé!

câu 3

2Al + 3Cl2 --t--> 2AlCl3

AlCl3 + 3NaOH -> 3NaCl + Al(OH)3

2Al(OH)3 -t-> Al2O3 + H2O

Al2O3 + 3H2SO4 -> Al2(SO4)3 + 3H2O

Al2(SO4)3 + 3BaCl2 -> 3BaSO4 + 2AlCl3

2AlCl3 + 3Mg -> 2Al + 3MgCl2

\(\left(1\right)4Al+3O_2\underrightarrow{t^o}2Al_2O_3\\ \left(2\right)Al_2O_3+6HCl\rightarrow2AlCl_3+3H_2O\\ AlCl_3+3NaOH\rightarrow Al\left(OH\right)_3\downarrow+3NaCl\\ 2Al\left(OH\right)_3\underrightarrow{t^o}Al_2O_3+3H_2O\\ 2Al_2O_3\underrightarrow{dpnc}4Al+3O_2\\ 2Al+6HCl\rightarrow2AlCl_3+3H_2\)